if there is explorace, so math race also held.. you know??
my institute teaching held mathrace. it very interesting. every students that participated in this mathrace, they said very happy.. and say math is fun.. there are many activities to put in math race. this is my banner for mathrace.. i will show ur activity in mathrace soon..

Have you ever wanted to teach your child some simple math tricks that you learned many years ago but can't seem to remember them? Well you are not alone! With the amount of math tricks that are out there, it can be hard to remember all of them. Here are a few to help refresh your mind for you.

A lot of children tend to get scared when they begin multiplication for 10 and up, but you can actually make things a little less scary for them. Usually by grade two a child is beginning to learn how to multiply things by the number eleven and many struggle, so teach your child this little trick and they'll love you forever for it.

Let go through an example so you can visually see by what I mean when I say you can literally multiple anything by eleven. Let's use the following equation:

11 x 45

Now with the numbers you are multiplying eleven with separate them with a space so you are now given the individual numbers 4 & 5. Now add these to numbers together which will get you 9. Now here comes the easiest part ever. Where you placed the space between the numbers 4 & 5 place the number 9 and you'll now have the total of 11 x 45= 495

Now if your child gets caught with a double digit number teach them this nifty little trick:

11 x 78

You will once again add these two numbers together which will give you 15. Let me show you what you'll need to do.

11x78 > 7 (7+8) 8 > 7 15 8 ... Now you will take the number 1 and add it onto the 7 which will then give you the answer of 858 for your answer. This trick is very simple and can let anyone truly get a better feel of doing their eleven times tables.

Now that you've learned how to do your eleven times table let's back track to the nine times table. This trick happens to be one of the most simplistic tricks anyone could ever learn and help a child really start out with their math.

When you are given a multiplication problem where you are multiplying 9 by 6 hold up both your hands in front of you, then you will begin counting from your left hand to the right hand till you hit the 6th finger, which would be your thumb. When you lower you thumb look at the fingers you have left on each hand. On your left hand you have 5 and on your right hand you have four. Place these two numbers together side by side and you'll have the answer of 54.

As you can see by using these two tricks you can really start your way to successfully starting your child's understanding of math. When a child finds that they are not struggling with math they are more likely to enjoy it, so teach them these two simple tricks and be on your way to have a child who loves participating in math.

Have you ever thought about doing complicated math as fast as a calculator? Do you believe this is impossible? Reconsider this notion! A lot of people are learning about the simple math methods that allow them to perform functions easily and you can do this too. This clever trick shows you how to multiply two numbers of two digits in your head in about 5 seconds.

Start with your base number. First you need to work out how far away your two numbers are from your base number. So if we take the example of multiplying 98 and 97 together, the closest base number to 98 and 97 is 100 - that is all you really need to know. It is necessary to be aware of your base number prior to doing the rest of the problem.

Think about how close these two digits are to the base number. Now calculate how far away your two numbers are from your base number. So 98 is 2 away from 100, and 97 is 3 away from 100. Just these two numbers are essential, so you should record them on top of the number - so write the -2 above the 98, and the -3 above the 97.

Cross-subtracting. Now this trick is something you probably have never seen before and it will certainly impress your friends! What you have to do now is cross-subtract. By that, take your first number which was 98 and the distance your second number is away from your base (-3) and subtract the two. To get technical, you would actually be adding the two, but to keep things straight in your mind, we'll call it subtraction). So, you'll get 98 minus 3 = 95. (You'll find that cross-subtracting with your other numbers works also, since 97 minus 2 = 95 too.) Keep that number 95 in mind, because it is the first two digits of your answer. (Can you believe we are half-way through calculating this mathematical problem!) Multiply the pair of numerals that are 'floating'. Now you multiply the two numbers you wrote above 98 and 97, which are -2 and -3. Negative times negative will always equal a positive number in multiplication - so your answer is simply, 6. Excellent! Don't let go of that number, either. It is the final number in the solution.

Examine the base in order to ascertain the way to express the final pair of numbers. At this point refer back to the base number one last time to find how many numbers there are and then take away one digit position. So if the number is 100 which has 3 places, you take away one digit spot which leaves you two placeholders or digit spots that need to be filled with the final number that you calculate. Come up with an answer. At this point, having computed each part of the problem (cross-subtraction along with multiplying) you will have your answer. Put them together to make the number 9506. And that's how easy it is to get the answer to 98 x 97. Demonstrate this method with any other two digit numbers and see if your friends/family are convinced that you are a human calculator!

A 1-Question IQ Test -- powered by flowgo.com

You may have heard the recent news of Dr. Gert Mittring, who correctly extracted the 13th root of a 100-digit number in less than 12 seconds...in his head. This article shows you how to accomplish the same feat in the same amount of time using an ordinary calculator.

This math article was inspired by the news article posted by our site administrator, Clay, who was kind enough to encourage me to resubmit my post as this present article for the interest of our readers.

The posted article reported how Dr. Gert Mittring, who has mastered mental calculations to a unimaginable level, managed to give the correct answer to extracting the 13th root of a 100 digit number in front of an audience and 2 umpires who selected the number at random. It was also reported that: "Spectators using electronic calculators were left minutes behind. "

If you read on, you will find out how you could outperform the spectators, calculator in hand! Just imagine the time it takes to input a 100 digit number is already more than 12 seconds!

If we were to be requested to count the number of grains of sand at a beach, most of us would stare on the white sand and say, how would I know. This is perfectly normal. For those of us who believe that it is possible, we will TRY and develop a method. Perhaps not the exact number, perhaps not even nearly exact, but it will be an approximation. From the approximation, we refine our method, and get even closer. This is how geniuses like Dr. Mittring work.

Now let us look at how we can solve the problem, with or without a calculator.

First, looking at the 13th root, by very simple calculations, we understand that:
ANY NUMBER RAISED TO THE 13TH POWER WILL HAVE THE LAST DIGIT OF THE RESULT EQUAL TO THAT OF THE ORIGINAL NUMBER.

That settles the last digit of the answer, simply by copying the last digit of the number to be extracted 13th root as the last digit of our answer!

Next, we would like to find out within what range the answers should be, given that the original number has to be a 100 digit number. Therefore the logarithm (to base 10) of the original number must be between 99.000 and 99.9999999...

Using an ordinary calculator, we calculate the numbers

99/13=7.61538462.. and 7.69230769230...

Raising 10 to these powers gives us the lower and upper limits as:
41246264 and 49238826.

In fact, the answers are as follows:

41246264 ** 13=1000000053891531265062238747077907560690804374410559722392499871913587301621661365915461814157574144

49238826 ** 13 =9999999162880950507644688918524814522347242627239243189376115437857450758590978444820365074927230976

So we know that the answers are 8 digit figures, starting with 4, in fact, between 41246264 and 49238826, with the last digit equal to the last digit of the given number!

We are already getting somewhere!

With this information in mind, now we are going to find the 13th root of a given 100-digit number using a calculator:

2345813452573965450990121027421105301917006585675372430552395152492628208920201161613694616524029952

If you are a mathematician, you probably have access to superior software such as Mathematica that will let you get the 13th root in a flash. If you are like the rest of us, with at best a good calculator in hand, this is how we could proceed:

We will find the logarithm (to base 10) of the number using the calculator. We won't be able to enter the complete number into most calculators, but we can do it approximately by noting that the number is nothing more than

2.3458134525739..*10^99 (that makes a number of 100 digits)

The logarithm is simply 99+log10(2.3458134525739)=99.3702934725

Divide the number by 13 to get 7.643868729

Calculate 10^(7.643868729) to get 44042172, which is the correct answer, noting that the last digit corresponds with the last digit of the original number!

So here it is, if you were with Dr. Mittring at the performance, with a calculator in hand, you could have beaten him with your answer in less than 11.8 seconds! For those of you who can preprogramme the calculator to do the task, the time it takes is what it takes to enter 10 digits.

44042172 ** 13 =2345813452573965450990121027421105301917006585675372430552395152492628208920201161613694616524029952

Happy Mental Calculations!


Note: The above calculations for raising to the power of 13 are thanks to a multi-digit calculator available at the following

Magic Square For All DigiT

Ask someone to name any digit, and you will make a magic square for that digit, so 'every' sum in the square gives you that digit.

SPECIAL RULE 11..

I think its special because you can directly write down the answer to any number multiplied by 11.

• Take for example the number 51236 X 11.
• First, write down the number with a zero in front of it.

  051236

  The zero is necessary so that the rules are simpler.

• Draw a line under the number.
• Bear with me on this one. It is simple if you work through it slowly. To do this, all you have to do this is "Add the neighbor". Look at the 6 in the "units" position of the number. Since there is no number to the right of it, you can't add to its "neighbor" so just write down 6 below the 6 in the units col.
• For the "tens" place, add the 3 to the its "neighbor" (the 6). Write the answer: 9 below the 3.
• For the "hundreds" place, add the 2 to the its "neighbor" (the 3). Write the answer: 5 below the 2.
• For the "thousands" place, add the 1 to the its "neighbor" (the 2). Write the answer: 3 below the 1.
• For the "ten-thousands" place, add the 5 to the its "neighbor" (the 1). Write the answer: 6 below the 5.
• For the "hundred-thousands" place, add the 0 to the its "neighbor" (the 5). Write the answer: 5 below the 0.
  That's it ... 11 X 051236 = 563596

amazing!!!! want more in easy maths...

Easy Multiply Up to 20X20 only in Your Hea

Mybe it impolsible to you, but I will show how to get it... In just FIVE minutes you should learn to quickly multiply up to 20x20 in your head.  With this trick, you will be able to multiply any two numbers from 11 to 19 in your head quickly, without the use of a calculator.

I will assume that you know your multiplication table reasonably well up to 10x10.

Try this:

• Take 15 x 13 for an example.
• Always place the larger number of the two on top in your mind.
• Then draw the shape of Africa mentally so it covers the 15 and the 3 from the 13 below. Those covered numbers are all you need.
• First add 15 + 3 = 18
• Add a zero behind it (multiply by 10) to get 180.
• Multiply the covered lower 3 x the single digit above it the "5" (3x5= 15)
• Add 180 + 15 = 195.

That is It! Wasn't that easy? Practice it on paper first!

When basic defenses won't suffice, sometimes even elementary knowledge of mathematics can keep you from spending hundreds or even thousands of dollars on your speeding ticket. Through explaining an extremely basic concept to the courtroom, you can give yourself an almost airtight defense to any speeding ticket, no matter if you were actually guilty of the infraction or not.

First off, we're going to start at the end of the concept and work our way backwards.

A vehicle moving at the rate of one mile per hour will cover 1.47 feet in one second.

To find out the distance a vehicle will cover in one second at any speed, simply multiply 1.47 by the desired speed. For instance, if a vehicle is traveling at 60mph, it will cover 88 feet in one second. For two second, obviously, it will cover 176 feet, and so on and so forth.

If you are trying to determine how many seconds it would take a vehicle to cover a known distance at a specific speed, simply divide the distance by the speed. Then divide the result by 1.47 feet.

This will yield the number of seconds it would take the vehicle to cover a known distance at a known speed.

For example: A vehicle traveling 60 mph will cover 300 feet in 3.4 seconds--300 divided by 60 divided by 1.47 = 3.4 seconds. If need be, you can verify this calculation by multiplying 3.4 seconds times 88 feet (the distance traveled in one second at 60 mph) and the result brings you back to 300 feet.

So, how does this apply to speeding tickets?

If you've been issued a VASCAR ticket, you should be given a few facts about your infraction. You should be told the speed you were traveling when clocked, the distance over which you were clocked, and the time it took you to cover that distance.

If the citation or incident report claims that you covered 300 feet in 4.2 seconds, and you are being charged with speeding at 60 mph in a 50 mph zone, you would be able to immediately prove the fallacy in your charges.

At 60 mph, you would have traveled 370 feet, not 300 feet. However, at 50 mph you would have traveled 309 feet in 4.2 seconds, indicating that you were clearly driving within the posted speed limit.

This proves that the charging officer(s) must have made a mistake in their calculations. Because this is the case, that particular set of evidence is thrown out the window. Being the primary piece of evidence in nearly all cases, too, the lack of said evidence would almost certainly clear you of all charges.